ok, wattage@1000 \divided by/ 120v = 8.3 amp draw
or for watt-1000 \/ 220v = 4.5 amp.
so @120v I can run 2-1000 lamps on a 20amp breaker on a #12-3 wire and I'll pull a 16.6 amp continuous load.
sounds a bit close?
but @220 i can still run a 20A *2-pole breaker* but only pull 13.5A continuous
that seems the better way to go but what about having 3 1000w lamps all kicking in
at once. is there a special consideration I need to know for that?
and this is what was said of the main feed for the sub-p
is this also the same for the wires and load on individual breakers?
or for watt-1000 \/ 220v = 4.5 amp.
so @120v I can run 2-1000 lamps on a 20amp breaker on a #12-3 wire and I'll pull a 16.6 amp continuous load.
sounds a bit close?
but @220 i can still run a 20A *2-pole breaker* but only pull 13.5A continuous
that seems the better way to go but what about having 3 1000w lamps all kicking in
at once. is there a special consideration I need to know for that?
and this is what was said of the main feed for the sub-p
is this also the same for the wires and load on individual breakers?
I believe your wire needs to be 1/0 or greater before you can run it in parallel. The lug on the breaker needs to be listed to accept two wires also.
And remember that those 6 lights are going to be considered a "continuous load", on for more than 3 hours, so you have to count the load as 125% of actual draw from the ballasts.