A minute - LOL.
We can start on it in a minute. Anybody got the pKa of dolomite. Also, any chemists wanna help, this equilibrium might get tricky.
Citrate molecule (C6H8O7) looks to be polyprotic - able to donate more than one hydrogen. From where I'm sitting - 3 of them. 3 -OH groups attached to C=O groups making them acidic.
Overall the equation should resenble this
4 C6H8O7 + 3 CaMg(CO3)2 -> 4 C6H5O73- + 3 Ca++ + 3 Mg++ + 6 H2CO3.
The pKa for citric acid is 3.13. Pka for carbonic acid (conjugate acid H2CO3) is 6.37. As the pKa of the reactant acid is higher than the product acid this reaction will proceed until the citric acid is consumed completely and excess dolomite is present. A start...
If the acid is not triprotic (donates three protons) the above is wrong.
Assuming I've half a clue. Chime in if I'm wrong! I'm reviewing acids/bases right now so it's convenient to do this stuff I'm not 'really' avoiding study he.
M [C6H8O7] = 192.124g mol L-1.
M [CaMg(CO3)2] = 184.41g mol L-1.
We can start on it in a minute. Anybody got the pKa of dolomite. Also, any chemists wanna help, this equilibrium might get tricky.
Citrate molecule (C6H8O7) looks to be polyprotic - able to donate more than one hydrogen. From where I'm sitting - 3 of them. 3 -OH groups attached to C=O groups making them acidic.
Overall the equation should resenble this
4 C6H8O7 + 3 CaMg(CO3)2 -> 4 C6H5O73- + 3 Ca++ + 3 Mg++ + 6 H2CO3.
The pKa for citric acid is 3.13. Pka for carbonic acid (conjugate acid H2CO3) is 6.37. As the pKa of the reactant acid is higher than the product acid this reaction will proceed until the citric acid is consumed completely and excess dolomite is present. A start...
If the acid is not triprotic (donates three protons) the above is wrong.
Assuming I've half a clue. Chime in if I'm wrong! I'm reviewing acids/bases right now so it's convenient to do this stuff I'm not 'really' avoiding study he.
M [C6H8O7] = 192.124g mol L-1.
M [CaMg(CO3)2] = 184.41g mol L-1.