How much electricity I am consuming?

[iamoni]

Hello everyone. I am duped on how power supplies work as I am not an electrical engineering but rather a hobbyist or a DIYer. I a, looking for cooling solutions and discovered the inverter technology. If I understood it correctly, the compressor is run by DC, running at variable speed for which whatever the system needs.
If I want to assemble a phase change system, using a DC compressor and I have a AC power source (residential) and convert it using a AC-DC converter, I do not know how much electricity I am consuming.

This is what I am thinking, and these are just examples for simplification. Supposedly that I use a Switching Mode Power supply,rated 10A, connect it to 220V AC the watt consumed is 2,200W. If I connect it to a load, DC, for example it outputs 12V, and the load uses 5A, so that is equal to 60W..
My question is, how much electricity I am consuming, and consequently have to pay? Is it 2,200W or 60W?

 

[Phaeton]

Consumed wattage versus available wattage. If the power supply is consuming 2200 watts then that is what must be paid for.
If only 60 watts are being consumed by the load then there is 2140 watts wasted as heat in the power supply. I do not believe there are products on the market capable of this.

I am guessing this is a problem with semantics more than an electrical problem.

I will use LED lights as an analogy. A 600 watt LED only consumes 250 through 350 watts, depending on brand.
The 600 watt rating is the maximum the diodes can consume without melting immediately. If they were actually run at that level they would burn out faster than an incandescent bulb.

The 2200 watt rating may be what the power supply can handle at maximum output. What is actually consumed is governed by the load. A 60 watt load will consume 60 watts, the available wattage does not come into play unless it is exceeded.

 

[cannaisok]

watt-meter, kill-a-watt devices ranging from 5-30dollar that will show u the amount of watts being used atm.

 

[AppliedScience]

^ Exactly. This is the only accurate way.

For a rough estimate just look up the spec sheet on the inverter.