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Calculating Fan Requirements for Your Indoor Garden

lokes

~Pollinator~
Veteran
Hi all, I thought this was a good read, so I thought I'd bring it over to share.


This article was hijacked from http://urbangardenmagazine.com/2009/04/calculating-fan-requirements-for-your-indoor-hydroponic-garden/



We asked two experienced growers (Dan from Oregon and Fred from The Netherlands) to face off with their different opinions on how to calculate your fan requirements. Whose method do you think is best?

Dan’s Method – Calculating By Room Volume

You will find many calculations on the web for sizing a fan for ventilating indoor gardens; however, what many of these calculations fail to take into consideration is the friction loss on carbon filters and increased temperatures from HID lights. So here’s my calculation method, which you can use as a guide for sizing an exhaust fan for a growing area. Keep in mind that this calculation will give you the lowest required CFM (Cubic feet of air per minute) required to ventilate the indoor garden.

Step 1 – Room Volume

First the volume of the room needs to be calculated. To calculate, multiply length x width x height of growing area. For example: a room that is 8′ x 8′ x 8′ will have a volume of 512 cubic feet.

Step 2 – CFM Required

Your extraction fan should be able to adequately exchange the air in an indoor garden once every three minutes. Therefore, 512 cubic feet / 3 minutes = 171 CFM. This will be the absolute minimum CFM for exchanging the air in an indoor garden.

Step 3 – Additional factors

Unfortunately, the minimum CFM needed to ventilate a indoor garden is never quite that simple. Once the grower has calculated the minimum CFM required for their indoor garden the following additional factors need to be considered:

* Number of HID lights: add 5% per air-cooled light or 10-15%
per non-air cooled light.
* CO2: add 5% for rooms with CO2 enrichment
* Filters: if a carbon filter is to be used with the exhaust
system then add 20%
* Ambient temperature for hot climates
(such as Southern California) add 25%; for
hot and humid climates (such as Florida) add up to 40%.

An Example

In our 8’ x 8’ room we have 2 x 1000w air cooled lights, and we plan to use a carbon filter. We also plan to use CO2 in this room. The ambient temperature is 90 °F (32 °C), however, we will be using air from another room that is air-conditioned. Here’s the minimum required CFM to ventilate the room:

1) Calculate the CFM required for room (see above).
2) Add 10% (for 2 air cooled lights).
3) Add 5% of original CFM calculation (for CO2).
4) Add 20% of original CFM calculation for the carbon filter.
5) Air is coming from an air-conditioned room so no need to add any other percentages.
6) CFM = (171CFM) + (171CFM x 10%) + 
(171CFM x 5%) + (171CFM x 20%) + ( 0 )
= 231CFM.

This is the absolute minimum CFM required to ventilate your room.

The next step might seem to match the closest fan to this CFM. However, for this example I’d choose a six inch fan with a CFM of around 400 or more, and a 6 inch carbon filter to match. The extra CFMs may seem a bit excessive (calculations on most indoor gardening websites would recommend a 4” fan and a 4” carbon filter) but it’s always better to over-spec since we need to compensate for air resistance in ducting too.

Also, as we are using a carbon filter we will need to match the fan with the filter so that the fan that will neatly fit onto the filter.

Note: If all the variables are kept the same and we changed the room size from 8’ x 8’ to a 12’ x 12’, then the minimum required CFM would be 519 CFM.
The All-Important Inflow!

An intake port can be anything from a gap under the door to an open window – even a hole in the wall. The best place for an intake port is diagonally opposite from your exhaust fan; that way, air has to pass across the entire room – very efficient. You can put a piece of screen over the opening to keep insects and animals out, a piece of A/C filter to keep dust out, or a louvered shutter or backdraft damper that opens when the fan turns on and closes when it turns off. You can also use a motorized damper. This gets installed in-line with your ducting and is plugged into whatever device controls your exhaust fan. When your fan turns on, it allows air to pass. When your fan shuts off, it seals completely, preventing CO2, air, etc. from passing. You can get creative with these devices and use one fan to control two rooms, etc.

One additional note about intake ports: you will see much better results from your exhaust system if you install a second fan to create an active (as opposed to passive) intake system. Normally, when your exhaust fan sucks air out of your room, air is passively going to get sucked back into the room. By installing a second fan on the intake side, you will reduce the amount of negative pressure created in the indoor garden, thereby cutting down greatly on the amount of work the exhaust fan has to do and allowing much more air to pass through. If you’re not sure or you don’t want to spend the money, start out with just an exhaust fan. If it’s not performing as well as you thought it would, try adding an intake fan – you’ll smile when you see the difference!


Fred’s Method – Calculating By Wattage

Hello there. First off, I’m used to working with Celsius, not Fahrenheit, but I’ve done my best to provide formulas for both. My method for calculating fan requirements does not cover active cooling with air conditioning systems or cool-tube designs. We’re talking about everyday grow chambers here, totally enclosed for air-flow control, with no large amounts of radiant heat into or out of the box. Your mileage may vary some for these reasons.

Right then, let’s get started:

1) Start at the beginning and design this right! Before you even buy or cut anything for your new project, determine the highest temperature that your intake air will ever be when lights run. Call this T (inlet).

2) Use these formulas to determine the difference in temperature you can tolerate. 80 °F (27 °C) is just about the optimal for growing most plants. You can go up to 76 °F (30°C) if you have to, but aim for 80 °F (27 °C).

Tdiff = 27 °C – T (temperature of inlet air)

3) Add up wattage for all power sources in your indoor garden. Lights, pumps, heaters, humidifier, radio, coffee maker, whatever! Add it ALL up and call it Watts. If it is on for more than three minutes and uses more than a watt, add it up. This will make your number worst-case and therefore a conservative value.

4) Compute the absolute minimum fan power you will need using the following formulas. Fan power is measured in the amount of air (cubic feet) shifted per minute. The formula below is the minimum fan rating you must have to achieve your temperature goals. You will have to increase fan power to compensate for duct constriction, small inlets, carbon scrubbers, screens, or other items that block airflow.

CFM = 1.75 x Watts / Tdiff (in Celsius)

If you prefer to work in Fahrenheit, try this formula:

CFM = 3 x Watts / Tdiff (in Fahrenheit)

5) Get at least this fan power or don’t come and ask questions! If you are going to have more than one fan, they should be mounted side-by-side rather than inline if you want to add their different CFM ratings. For inline fans, use the lowest air-flow rating of all fans in the path. A fan on the inlet and a fan on the exhaust of the box are considered inline fans. Fans just circulating air inside the indoor garden should not be counted for airflow but must be included in your initial wattage calculations.

Ok, to see these formulas in action we’re going to have to do a little number crunching:

An Example

Ok, let’s say you have 2000 watts in a 8 foot by 8 foot room with an 8 foot ceiling height.

So what amount of air do I need to move to keep the room at 82°F (28°C)? My incoming air temperatures are 68°F (20°C) during the lights on period.

Tdiff = 28 – 20 = 8°C

For Celsius the formula comes out at:

CFM = 1.75 x 2000 / 8 = 438 CFM

For Fahrenheit we get the following:

Tdiff = 82 – 68 = 14°F

CFM = 3 x 2000 / 14 = 429 CFM

Here’s a quick look-up chart to show some further examples:
Watts

CFM

Tdiff (Fahrenheit)
70 16 13
150 9 28
150 54 32
150 75 6
250 150 5
250 188 4
400 60 20
400 133 9
400 240 5
600 120 15
600 225 8
1000 15 189*
1000 142 21
1000 250 12

Remember, Tdiff shows how much your temperatures will rise above your inflow air temperature for a given wattage and air movement.

* Just a humorous example. 1000 watts of light with a PC computer fan (15 CFM) – temperatures rise 189°F according to this formula!

If you are adding any carbon scrubbers or extensive ductwork, this is where you add to the fan size to account for air pressure losses. You have to move this many CFM, or the numbers don’t come out right. Exactly how much these items diminish your airflow depends on your exact configuration and is beyond the scope of this introductory article!

What to do when your outside temperatures are higher than your maximum allowed indoor garden temperatures:

You have a few choices:

1) Stop growing for a while ’til things cool off, or try running your grow lamps at night when inlet air will be cooler.

2) Reduce your lighting to drop the heat load. Not good if the incoming air is already over critical when it arrives in the box. Might be possible if the inlet air temperature is lower but you are running too many lights to keep up with the cooling.

3) Use active air conditioning.
 

stratagem

New member
So according to this:

My flower chamber = 2.25' x 2.25' x 5.5'
My veg chamber = 1.25' x 2.25' x 5.5'

Total = 43.3125 cubic feet

3 air changes per minute = 14.4375 CFM

Without a cooltube or vented hood = 16.603125 CFM

With a carbon filter = 19.92375 CFM

No added Co2 and don't live in hot and humid climate.

Highest temperature would be 85-90 degrees (but rare).

TDiff is 80 F - 90 F = 10 F

All wattage is 400W HPS + 168W CFLs (4 42W) = 568W

3 * 568 / 10 = 170.4 CFM

So which is it? 19.92 CFM or 170 CFM? Why even calculate the first one?

And why is it 1 air change per 3 minutes and not 3 air changes per minute?

None of this seems to make sense to me honestly.
 

lokes

~Pollinator~
Veteran
So which is it? 19.92 CFM or 170 CFM? Why even calculate the first one?

And why is it 1 air change per 3 minutes and not 3 air changes per minute?

None of this seems to make sense to me honestly.

Strata, glad to see someone uses info around here. Okay, to try and answer your questions, remember I didn't write this so I'll do my best.

And why is it 1 air change per 3 minutes and not 3 air changes per minute? 1 air change per 3 minutes is correct. Remember we are trying to calculate the minimum only.

So which is it? 19.92 CFM or 170 CFM? Why even calculate the first one? This is where I'm going out on a limb. I believe they are both correct. After checking all your numbers (which are right) I kind of read between the lines when I reread the two different methods.

I believe the first method is addressing ONLY air exchange in the room requiring the lower CFM.

The second method is addressing the air exchange needed to maintain optimal temps. Therefore a higher exchange rate is needed, but no A/C

How'd I do?
 

inthefire

Member
Hey lokes can you explain the Dans method i cant seem to figure out the math when i add everything up for his example the 231CFM i get numbers that are way off.Im not even high.
thanks
 

GHUA

Member
This seems odd.

Let's say you use a DR120 tent (120cmx120cmx200cm or 4x4x6feet). With a cooltube and a scrubber, the first method would be 96cubic feet/3. This comes out to 32. Even when you add the 25% for scrubber and cooltube, it comes out 40CFM or 68m3/h... I may be really new, but this seems to conflict with what a lot of smart people (on ICMAG for instance) say!

The other formula requires Wattage, and I plan on using a 600W HID. A normal (warm) house will probably 24°C or so, on hottest summer days. I assume most people, like myself, wont have radios and whatnot in their growtent, so lets just keep it at 600W plus two clipon fans (30W each) to be safe. This means 1.75x660W/3 which SHOULD be 385CMF or 654m3/h

I think this is pretty radical differences, and while formula nr. 2 probably wont burn down your grow it seems like they are both lacking in variables, which is what the whole article is about, but maybe I misunderstood number 1?

I believe the first method is addressing ONLY air exchange in the room requiring the lower CFM.

The second method is addressing the air exchange needed to maintain optimal temps. Therefore a higher exchange rate is needed, but no A/C
I don't think I understand how the first method would be useful, since with a 60CFM fan i would not only have sub-optimal temperatures, it seems I may have a fire or at least burning the plants crisp?
 
2

2Lazy

The second formula is really useless. Suppose your intake temperature can get to 76 degrees. Your optimal temperature is also 76 degrees. Which makes Tdiff=0. A 2000w setup would need 6000cfm according to the Fahrenheit formula.

Unfortunate that this didn't help me out much at all.

I think a better approach would be to measure the output of the light in BTU.
According to Howstuffworks.com a single 1000w bulb requires the cooling of about 2,800 BTU. Making it much further from here would be to overestimate my understanding of thermodynamics as they relate to air flow.

But --- According to wikianswers.com it takes 0.018btu to raise the temperature of 1 cubic foot of air 1 degree Fahrenheit.

So here's how I look at it:
2800btu / 0.018btu (per cuft) = 155,555 cuft
Now I need to determine how many minutes there are in a 12 hour flowering period.
12 hours * 60 minutes = 720 minutes

Finally I take my cooling requirement of 2,800 BTU broken down as best I can into cuft of air and divide by the number of minutes the cooling is required.

155,555 cuft / 720 minutes = 216 cuft / minute (CFM)

Obviously there are a lot of factors to take into account; intake temperature, room volume, exhaust rate with respect to contact time with the heat source... I suppose there are too many factors to get a precise equation the layman can utilize.

Yet, I feel this is an acceptable average and that the math is sound despite the numbers being a little "fabricated" and not necessarily accurate. 216CFM seemed like a good number to just stumble upon with a little application of thought so I'm going to run with it and hope for the best.

As I understand it so long as all the air in the room can be vented every 1 to 2 minutes then the heat shouldn't build up to a level more than a few degrees warmer than the intake. As long as the intake is within 5 to 6 degrees of the target then exhausting the grow room quickly eliminates the need for any guesswork and half-assed attempts at making any sense of these equations.
 
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